Guy connects 244 9v batteries in a row...
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2. Geekster (admin) commented 10 years ago
Well, batteries are rated in amp/hours, a 9V battery has between 500 and 800 mAh(milliamphours). If you put the batteries in series then the amperage will stay the same, only the voltage will be bigger. If you put the batteries in parallel then the amperage will be higher, but the voltage will be lower. That depends on the configuration that you make. For example: if you have 2 batteries (each has 1.5V and 500 mAh), if you put them in series then you will have 3V and 500 mAh, but if you put them in parallel you will have 1.5V but 1000 mAh.
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3. orion commented 10 years ago
#2 you mixed up some quantities. Capacity (mAh) is the amount of charge. That has nothing to do with current you can get out of it, only how long it takes to empty it. Also, amp*hours (times, not division, that's crucial here). Notice mili (1/1000) times A (ampere) times h (hour): the more current you have, the less time you can use the battery, the product staying the same.
If you put batteries in a series, voltages add together, but the current only depends on the resistance: on how much load you put on it, and the internal resistance of the batteries. If you short-circuit it, the only thing that matters is the resistance of the battery itself, and if that's too low, the current is enough to overheat and destroy the battery. The resistance of the battery is quite difficult to guess, you have to measure it (by measuring the current, for instance)! You need U=R*I (voltage equals resistance times current: more resistance means less current and vice-versa).
If you put batteries in a series, voltages add together, but the current only depends on the resistance: on how much load you put on it, and the internal resistance of the batteries. If you short-circuit it, the only thing that matters is the resistance of the battery itself, and if that's too low, the current is enough to overheat and destroy the battery. The resistance of the battery is quite difficult to guess, you have to measure it (by measuring the current, for instance)! You need U=R*I (voltage equals resistance times current: more resistance means less current and vice-versa).
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4. JohnMichael commented 10 years ago
The first comment asked about the amperage, so why even mention capacity? If you can weld with it is far mor interesting than "how long is that huge battery going to last if I decide to try and weld with it?"..
Thankfully #3 came around and corrected the oblivious #2..
Thankfully #3 came around and corrected the oblivious #2..
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5. cameramaster commented 10 years ago
I was waiting to see him test the voltage with his tongue :-/
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About this video
Category: Other
Published: 10 years ago
Submitted by: Geekster
Views: 3,708
Rating:
(69 votes)
Length: 7:10 minutes
Filesize: 71.3 megabytes
Dimensions: 1024 × 576 px
+7 1. sux2bu commented 10 years ago
I am sure you could weld with it.